The Sum of Two Numbers is 98 and Their Difference is 6

The sum of two numbers is 98 and their difference is 6. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 98. In other words, x plus y equals 98 and can be written as equation A:

x + y = 98

The difference between x and y is 6. In other words, x minus y equals 6 and can be written as equation B:

x - y = 6

Now solve equation B for x to get the revised equation B:

x - y = 6
x = 6 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 98
6 + y + y = 98
6 + 2y = 98
2y = 92
y = 46

Now we know y is 46. Which means that we can substitute y for 46 in equation A and solve for x:

x + y = 98
x + 46 = 98
X = 52

Summary: The sum of two numbers is 98 and their difference is 6. What are the two numbers? Answer: 52 and 46 as proven here:

Sum: 52 + 46 = 98
Difference: 52 - 46 = 6

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The Sum of Two Numbers is 98 and Their Difference is 7
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