The Sum of Two Numbers is 98 and Their Difference is 7

The sum of two numbers is 98 and their difference is 7. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 98. In other words, x plus y equals 98 and can be written as equation A:

x + y = 98

The difference between x and y is 7. In other words, x minus y equals 7 and can be written as equation B:

x - y = 7

Now solve equation B for x to get the revised equation B:

x - y = 7
x = 7 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 98
7 + y + y = 98
7 + 2y = 98
2y = 91
y = 45.5

Now we know y is 45.5. Which means that we can substitute y for 45.5 in equation A and solve for x:

x + y = 98
x + 45.5 = 98
X = 52.5

Summary: The sum of two numbers is 98 and their difference is 7. What are the two numbers? Answer: 52.5 and 45.5 as proven here:

Sum: 52.5 + 45.5 = 98
Difference: 52.5 - 45.5 = 7

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The Sum of Two Numbers is 98 and Their Difference is 8
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