The Sum of Two Numbers is 48 and Their Difference is 7

The sum of two numbers is 48 and their difference is 7. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 48. In other words, x plus y equals 48 and can be written as equation A:

x + y = 48

The difference between x and y is 7. In other words, x minus y equals 7 and can be written as equation B:

x - y = 7

Now solve equation B for x to get the revised equation B:

x - y = 7
x = 7 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 48
7 + y + y = 48
7 + 2y = 48
2y = 41
y = 20.5

Now we know y is 20.5. Which means that we can substitute y for 20.5 in equation A and solve for x:

x + y = 48
x + 20.5 = 48
X = 27.5

Summary: The sum of two numbers is 48 and their difference is 7. What are the two numbers? Answer: 27.5 and 20.5 as proven here:

Sum: 27.5 + 20.5 = 48
Difference: 27.5 - 20.5 = 7

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The Sum of Two Numbers is 48 and Their Difference is 8
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