The Sum of Two Numbers is 48 and Their Difference is 8

The sum of two numbers is 48 and their difference is 8. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 48. In other words, x plus y equals 48 and can be written as equation A:

x + y = 48

The difference between x and y is 8. In other words, x minus y equals 8 and can be written as equation B:

x - y = 8

Now solve equation B for x to get the revised equation B:

x - y = 8
x = 8 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 48
8 + y + y = 48
8 + 2y = 48
2y = 40
y = 20

Now we know y is 20. Which means that we can substitute y for 20 in equation A and solve for x:

x + y = 48
x + 20 = 48
X = 28

Summary: The sum of two numbers is 48 and their difference is 8. What are the two numbers? Answer: 28 and 20 as proven here:

Sum: 28 + 20 = 48
Difference: 28 - 20 = 8

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The Sum of Two Numbers is 48 and Their Difference is 9
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