The Sum of Two Numbers is 48 and Their Difference is 6

The sum of two numbers is 48 and their difference is 6. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 48. In other words, x plus y equals 48 and can be written as equation A:

x + y = 48

The difference between x and y is 6. In other words, x minus y equals 6 and can be written as equation B:

x - y = 6

Now solve equation B for x to get the revised equation B:

x - y = 6
x = 6 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 48
6 + y + y = 48
6 + 2y = 48
2y = 42
y = 21

Now we know y is 21. Which means that we can substitute y for 21 in equation A and solve for x:

x + y = 48
x + 21 = 48
X = 27

Summary: The sum of two numbers is 48 and their difference is 6. What are the two numbers? Answer: 27 and 21 as proven here:

Sum: 27 + 21 = 48
Difference: 27 - 21 = 6

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The Sum of Two Numbers is 48 and Their Difference is 7
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