The Sum of Two Numbers is 32 and Their Difference is 7




The sum of two numbers is 32 and their difference is 7. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 32. In other words, x plus y equals 32 and can be written as equation A:

x + y = 32

The difference between x and y is 7. In other words, x minus y equals 7 and can be written as equation B:

x - y = 7

Now solve equation B for x to get the revised equation B:

x - y = 7
x = 7 + y


Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 32
7 + y + y = 32
7 + 2y = 32
2y = 25
y = 12.5


Now we know y is 12.5. Which means that we can substitute y for 12.5 in equation A and solve for x:

x + y = 32
x + 12.5 = 32
X = 19.5


Summary: The sum of two numbers is 32 and their difference is 7. What are the two numbers? Answer: 19.5 and 12.5 as proven here:

Sum: 19.5 + 12.5 = 32
Difference: 19.5 - 12.5 = 7



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