The Sum of Two Numbers is 32 and Their Difference is 8

The sum of two numbers is 32 and their difference is 8. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 32. In other words, x plus y equals 32 and can be written as equation A:

x + y = 32

The difference between x and y is 8. In other words, x minus y equals 8 and can be written as equation B:

x - y = 8

Now solve equation B for x to get the revised equation B:

x - y = 8
x = 8 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 32
8 + y + y = 32
8 + 2y = 32
2y = 24
y = 12

Now we know y is 12. Which means that we can substitute y for 12 in equation A and solve for x:

x + y = 32
x + 12 = 32
X = 20

Summary: The sum of two numbers is 32 and their difference is 8. What are the two numbers? Answer: 20 and 12 as proven here:

Sum: 20 + 12 = 32
Difference: 20 - 12 = 8

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The Sum of Two Numbers is 32 and Their Difference is 9
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