The Sum of Two Numbers is 98 and Their Difference is 4

The sum of two numbers is 98 and their difference is 4. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 98. In other words, x plus y equals 98 and can be written as equation A:

x + y = 98

The difference between x and y is 4. In other words, x minus y equals 4 and can be written as equation B:

x - y = 4

Now solve equation B for x to get the revised equation B:

x - y = 4
x = 4 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 98
4 + y + y = 98
4 + 2y = 98
2y = 94
y = 47

Now we know y is 47. Which means that we can substitute y for 47 in equation A and solve for x:

x + y = 98
x + 47 = 98
X = 51

Summary: The sum of two numbers is 98 and their difference is 4. What are the two numbers? Answer: 51 and 47 as proven here:

Sum: 51 + 47 = 98
Difference: 51 - 47 = 4

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The Sum of Two Numbers is 98 and Their Difference is 5
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