
The sum of two numbers is 71 and their difference is 4. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.
The sum of x and y is 71. In other words, x plus y equals 71 and can be written as equation A:
x + y = 71
The difference between x and y is 4. In other words, x minus y equals 4 and can be written as equation B:
x - y = 4
Now solve equation B for x to get the revised equation B:
x - y = 4
x = 4 + y
Then substitute x in equation A from the revised equation B and then solve for y:
x + y = 71
4 + y + y = 71
4 + 2y = 71
2y = 67
y = 33.5
Now we know y is 33.5. Which means that we can substitute y for 33.5 in equation A and solve for x:
x + y = 71
x + 33.5 = 71
X = 37.5
Summary: The sum of two numbers is 71 and their difference is 4. What are the two numbers? Answer: 37.5 and 33.5 as proven here:
Sum: 37.5 + 33.5 = 71
Difference: 37.5 - 33.5 = 4
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The Sum of Two Numbers is 71 and Their Difference is 5
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