The Sum of Two Numbers is 56 and Their Difference is 8

The sum of two numbers is 56 and their difference is 8. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 56. In other words, x plus y equals 56 and can be written as equation A:

x + y = 56

The difference between x and y is 8. In other words, x minus y equals 8 and can be written as equation B:

x - y = 8

Now solve equation B for x to get the revised equation B:

x - y = 8
x = 8 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 56
8 + y + y = 56
8 + 2y = 56
2y = 48
y = 24

Now we know y is 24. Which means that we can substitute y for 24 in equation A and solve for x:

x + y = 56
x + 24 = 56
X = 32

Summary: The sum of two numbers is 56 and their difference is 8. What are the two numbers? Answer: 32 and 24 as proven here:

Sum: 32 + 24 = 56
Difference: 32 - 24 = 8

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The Sum of Two Numbers is 56 and Their Difference is 9
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