The Sum of Two Numbers is 49 and Their Difference is 7

The sum of two numbers is 49 and their difference is 7. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 49. In other words, x plus y equals 49 and can be written as equation A:

x + y = 49

The difference between x and y is 7. In other words, x minus y equals 7 and can be written as equation B:

x - y = 7

Now solve equation B for x to get the revised equation B:

x - y = 7
x = 7 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 49
7 + y + y = 49
7 + 2y = 49
2y = 42
y = 21

Now we know y is 21. Which means that we can substitute y for 21 in equation A and solve for x:

x + y = 49
x + 21 = 49
X = 28

Summary: The sum of two numbers is 49 and their difference is 7. What are the two numbers? Answer: 28 and 21 as proven here:

Sum: 28 + 21 = 49
Difference: 28 - 21 = 7

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The Sum of Two Numbers is 49 and Their Difference is 8
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