The Sum of Two Numbers is 43 and Their Difference is 21

The sum of two numbers is 43 and their difference is 21. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 43. In other words, x plus y equals 43 and can be written as equation A:

x + y = 43

The difference between x and y is 21. In other words, x minus y equals 21 and can be written as equation B:

x - y = 21

Now solve equation B for x to get the revised equation B:

x - y = 21
x = 21 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 43
21 + y + y = 43
21 + 2y = 43
2y = 22
y = 11

Now we know y is 11. Which means that we can substitute y for 11 in equation A and solve for x:

x + y = 43
x + 11 = 43
X = 32

Summary: The sum of two numbers is 43 and their difference is 21. What are the two numbers? Answer: 32 and 11 as proven here:

Sum: 32 + 11 = 43
Difference: 32 - 11 = 21

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The Sum of Two Numbers is 43 and Their Difference is 22
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