The Sum of Two Numbers is 41 and Their Difference is 6

The sum of two numbers is 41 and their difference is 6. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 41. In other words, x plus y equals 41 and can be written as equation A:

x + y = 41

The difference between x and y is 6. In other words, x minus y equals 6 and can be written as equation B:

x - y = 6

Now solve equation B for x to get the revised equation B:

x - y = 6
x = 6 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 41
6 + y + y = 41
6 + 2y = 41
2y = 35
y = 17.5

Now we know y is 17.5. Which means that we can substitute y for 17.5 in equation A and solve for x:

x + y = 41
x + 17.5 = 41
X = 23.5

Summary: The sum of two numbers is 41 and their difference is 6. What are the two numbers? Answer: 23.5 and 17.5 as proven here:

Sum: 23.5 + 17.5 = 41
Difference: 23.5 - 17.5 = 6

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The Sum of Two Numbers is 41 and Their Difference is 7
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