The Sum of Two Numbers is 41 and Their Difference is 3

The sum of two numbers is 41 and their difference is 3. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 41. In other words, x plus y equals 41 and can be written as equation A:

x + y = 41

The difference between x and y is 3. In other words, x minus y equals 3 and can be written as equation B:

x - y = 3

Now solve equation B for x to get the revised equation B:

x - y = 3
x = 3 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 41
3 + y + y = 41
3 + 2y = 41
2y = 38
y = 19

Now we know y is 19. Which means that we can substitute y for 19 in equation A and solve for x:

x + y = 41
x + 19 = 41
X = 22

Summary: The sum of two numbers is 41 and their difference is 3. What are the two numbers? Answer: 22 and 19 as proven here:

Sum: 22 + 19 = 41
Difference: 22 - 19 = 3

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The Sum of Two Numbers is 41 and Their Difference is 4
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